1.	(a)	5, -1	2
B1 for each correct answer
(b)		2
B1 ft for all 7 points plotted correctly
B1 ft for smooth curve through 7 points (dep on B1 in (a))
(c)	-1.25	1
B1 ft ± ½ square – must have single minimum from a curve through 6 points
(d)		3
B1 for line y = 2x – 4 drawn correctly.
B1 + B1 ft (dep on line of gradient 2, or intercept of – 4) for each correct answer.
Answers are 3.62 and 1.38
OR B1 y = x2 - 5x + 5 seen and attempt to plot
B1 values (1, 1) (2, -1) (3, -1) (4, 1)
B1 ft for 2 solutions
[8]

2.	6, - 3	3
	(x - 6)(x + 3)
M2 for (x - 6)(x + 3)
(M1 for (x ± 6)(x ± 3))
A1 cao for 6 and -3
[3]

3.	

x = 6.2749 or x = –1.2749
6.27 or –1.27	3
M1 for correct substitution into formula up to signs on b and c
M1 for 
A1 6.27 to 6.275 and –1.27 to –1.275
[3]

4.	a = 49
b = –7	3
M1 for (x )2–()2 or x2+bx + bx + b2
A1 for  a = 49
A1 for  b = -7 or (x – 7)2
[3]

5.	(a)	Printed result shown convincingly	4
	(2x + 3)(x + 4) – (x + 2)2 = 20
2x2 + 3x  + 8x + 12 – (x2 + 4x +4) = 20
2x2 + 3x  + 8x + 12 – (x2 + 4x +4) – 20 =0
2x2 + 3x  + 8x + 12 – x2 – 4x – 4 –20 =0
x2 + 7x – 12 = 0
M1 for (2x + 3)(x + 4) – (x + 2)2 = 20 oe
M1 for at least 3 terms correct in an expansion
A1 for 2x2 + 3x  + 8x + 12 – (x2 + 4x +4) – 20 =0
A1 for full valid completion to printed result
(b)	(i)	1.424, -8.424	3

x = 1.424428…..; − 8.424428…..
M1 for 
A1 for 
A1 for 1.424 , − 8.424
(ii)	13.7	1
	Perimeter = 4(1.4244..+2)
B1ft (only follow through on 0<x<2.472 )
[8]

6.	x = 1.31m	5
	0.5 ´ (2x + 1) ´ (x + 2) ´ sin 30 = 3
0.25 ´ (2x2 + 4x + x +2) = 3
2x2 + 5x + 2 = 12
2x2 + 5x - 10 = 0
x = 
= 1.311737...
M1 for 0.5 ´ (2x + 1) ´ (x + 2) ´ sin 30 or used
M1 (dep) ... = 3 and an attempt to expand algebraic brackets
A1 oe in form ax2 + bx + c = d
M1 ft (dep on 1st 2 M1s) for correct process to solve quadratic equation
A1 for 1.31 or better
[5]